Friday 1 May:

Journal:  What happens to the wave's velocity on a stretched string when the tension in a string is doubled?

V = √ T/M_L   (velocity of waves on a string)

Increase by √2

What happens if the string’s mass is doubled?

V = √ T/M_L

    a. goes down by √1/2

A standing wave of 5 segments, as is set on a string 10 meters long. a. What is the wavelength (l) this wave.

b. What is the wave length of the string’s fundamental frequency.

c. The wave’s velocity (if the fundamental frequency is 15Hz)?  

a.       Two Segments = one l. Therefore, 2/5 of 10m   is 4.0m

b.        One segment = 10m. 1/2 l is 10m, therefore one l is 20.0m

c.        V = f l   à  V = (15)(20) = 300m/s

L#78: 1- 2, 8, 11, 12, 14, 15 -19

& L#79: 3, 4, 8

(due Friday May 1 - Standing Waves)  

Test Tuesday/Wed:    69, 70, 71, 74, 78