Monday Apr 14th:

 

Key Concept(s) Today: Lenses

 

Journal: What happens to ice on a bridge when you put NaCl on it? Explain

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

L#69: 1- 3, 6, 10, 16, 18 (Due Monday) (Lenses)

 

 

Lenses:

 

 

 

 

 

 

 

 

http://dev.physicslab.org/Document.aspx?doctype=3&filename=GeometricOptics_ConvergingLenses.xml

         

 

 

 

 Lenses: Location of image

  •  NF:  Near Focus (side near eye/opposite side from object)

  •  FF:  Far Focus (side opposite of eye/same side as object)

 Draw: Concave/Converging Lens:

diagram

          1. Pà NF

                             2. FFà P

3. May use centerline (from top of object through dead center of lense) à top of image will also be on centerline)

 

 

 

       Draw: Convex/Diverging Lens:      

 

                             1. Pà FF

                             2. NFà P

3. May use centerline (from top of object through center à  top of image will also be on centerline)

 

 

 

 

 

 

L#70: 1- 4,  7, 8, 10, 11, 18, 20 (due Friday 17th) (Static/Induced Charges)

 

Bridge Building: Friday

 

 

#71: 1- 4,  6 - 8, 10, 13 - 17

(due Wed/Thurs 20/21 Apr) (Pendulum)

 

 

 

 

 

Lab: Friday

 

Key Concept(s) Today: Temp & Heat, Review (W/S)

 

L#69: 1- 3, 6, 10, 16, 18 (due Today) (Lenses)

 

 

Lenses:

 

 

 

 

 

Demo:

http://webphysics.davidson.edu/Course_Material/Py230L/optics/lenses.htm

 

 

 

 

1. An 1.0m object is placed 2.5 meters from a converging lens (f = 1.0m). Find

a. location  

b. orientation

c. distance from lens

d. size of image

e. magnification of image.

 

 

 

 

 

 

 

 

diagram

 

 

 

 

 Answers: a. Real (same side as eye)

                 b. Up-side-down/inverted

                 c. about 2.0 m

                 d. about .75 m

                 e.  M=Hi/Ho

                      .75/1.0 = .75 of 3/4

 

 

2. Davin (4.0m tall) is placed 8.0 meter from a diverging lens (f = 3.0m). Find

a. location  

b. orientation

c. distance from lens

d. size of image

e. magnification of image.

 

 

 

 

 

 

 

 

 

 Answers: a. Virtual (opposite side as eye)

                 b. Upright

                 c. about 2.0m

                 d. about 2.0m

                 e.  M=Hi/Ho

                      2.0/4.0 = 0.5

 

Davin’s image is Virtual, Upright, and Shorter than the real Davin.

 

Some would say that Davin’s image

looks better than Davin himself.

 

 

 

 

 

 

L#70: 1- 4, 7, 8, 11, 18, 20 (due Monday 14th) (Static/Induced Charges)

 

 

 Lab: Tues 15th / Wed 16th Don't give me any Static

 

 

#71: 1- 4, 6 - 8, 13 - 17

(due Thurs/Fri 17/18th) (Pendulum)

 

 

Monday (21st): Tower Contest

 

 

 

L#74: 1- 2, 7, 10, 13, 15, 16, 18, 20

(due Tuesday 22th) (2nd law of Thermodynamics)

 

 

L#78: 1- 2, 8, 11, 12, 14, 15 -19

(due Friday 25th) (Standing Waves)

 

 

L#70: 1- 4, 10, 7, 8, 11, 18, 20 (due Today 14th) (Static/Induced Charges)

 

 

 Lab: Tues 15th / Wed 16th Don't give me any Static

 

 

#71: 1- 4, 10, 6 - 8, 13 - 17

(due Thurs/Fri 17/18th) (Pendulum)

 

 

Monday (21st): Tower Contest

 

 

L#74: 1- 2, 7, 10, 13, 15, 16, 18, 20

(due Tuesday 22th) (2nd law of Thermodynamics)

 

 

L#78: 1- 2, 8, 11, 12, 14, 15 -19

(due Friday 25th) (Standing Waves)

 

Lab: Tues 29th / Standing Waves