Qs (energy to heat a solid): (m)(cs)(DT)
Qs-L (energy for phase change S-->L): (m)(HHeat of Fusion)
QL (energy to heat a liquid): (m)(cL)(DT)
Qs (energy for phase change L-->V): (m)(HHeat of Vaporization)
QV(energy to heat a vapor): (m)(cV)(DT)
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Friday 30 Jan:
Key Concept's) Today: Simple machines & forces/stress/strain/compression
Pd 2:
Mini- Lab (no written procedures or material) just Hypothesis, Data, & Conclusion
Finish structures
Think of ways to gather Data for Testing on Monday (All Structures):
On Monday, be ready to talk about:
W/S: Simple MachinesLab: Buoyancy (Monday) Pd 1Lab: Tower (Monday) Pd 2
L#38: 1,2, 5-6, 9, 13, 15, 18 (Due Tuesday 1st) ****L #37: 1-4, 7-9, 11-13 (due Wed 3 Feb) Lab: Electrical Circuits (Thurs 4 Feb) L#39: 1- 6, 9, 10, 12, 14, 17, 18 - 20 (due Mon 8 Feb)
L#40: 1-7, 9, 11, 15, 16, 18, 19 (due Wed 10 Feb)
Volt: Potential (like height & steepness of a hill) Amp: Current (like amount of water in a stream or river) Resistance (ohms - Ω ): (like friction - stops the flow of electricity)
Lab: Circuits Thurs 4 Feb
Notes: L#39
http://www.miamisci.org/af/sln/phases/waterempty.html
Water’s
temperature does not change during phase
transitions as heat flows into or out of it.
Qs (energy to heat a solid): (m)(cs)(DT) Qs-L (energy for phase change S-->L): (m)(HHeat of Fusion) QL (energy to heat a liquid): (m)(cL)(DT) Qs (energy for phase change L-->V): (m)(HHeat of Vaporization) QV(energy to heat a vapor): (m)(cV)(DT)
Example: How much energy does it take to change 2-kg of Cu from 9830C to 15870C (HF = 135x103; HV = 5,070x103, cS = 400, cL = 500, cV = 200)
Qs (energy to heat a solid): (m)(cs)(DT) (2)(400)(100) = 80,000J Qs (energy for phase change S-->L): (m)(HHeat of Fusion) (2)(135x103) = 270,000J QL (energy to heat a liquid): (m)(cL)(DT) (2)(500)(104) = 104,000J Qs (energy for phase change L-->V): (m)(HHeat of Vaporization) (2)(5,070x103) = 10,140,000J QV(energy to heat a vapor): (m)(cV)(DT) (2)(200)(400) = 160,000J 10,754,000
Lab: Ohm's Law The fundamental relationship among the three important electrical quantities current, voltage, and resistance was discovered by Georg Simon Ohm.. In this experiment you will see if Ohm’s law is applicable to several different circuits using a Current Probe and a Voltage Probe. Current and voltage cannot be observed directly. To clarify these terms, some people make the comparison between electrical circuits and water flowing in pipes. Here is a chart of the three electrical units we will study in this experiment.
Figure 1 Black wire Red wire + -
(Red side) (Black side) Amps Probe (in line)
(on both sides of resistor) Questions · What is the mathematical relationship between current, potential difference, and resistance in a simple circuit? MATERIALS
Hypothesis: 1. If the electrical potential is increased, then the current through normal 10 W resistor (decreases, remains constant, or increases) proportionally because …. 2. If the electrical potential is increased, then the current through light bulb (decreases, remains constant, or increases) proportionally because… Pre-Lab & PRELIMINARY Questions:
PRELIMINARY SEtup: 1. Connect the Current Probe to Channel 1 and the Differential Voltage Probe to Channel 2 of the computer interface. 2. Open the file “25 Ohms Law” in the Physics with Computers folder. A graph of potential vs. current will be displayed. 3. With the power supply turned off, connect the power supply, 10 W resistor, wires, and clips as shown in Figure 1. Take care that the positive lead from the power supply and the red terminal from the Current & Voltage Probe are connected as shown in Figure 1. Note: Attach the red connectors electrically closer to the positive side of the power supply.
4. Click
5. IMPORTANT! Turn the control on the DC power supply to 0 Volt. However, turn the “Current” Knob (AMP) slightly to the right (about 1/10 of a turn), so that the “red light” (“Limited Current”) is off. 6. Have your teacher check the set-up arrangement before proceeding. PROCEDURE 1. Record the value of the resistor in the data table. Condition #1 (10 W resistor): 2. Turn on the power supply. Click
3. Read
Carefully: Now slowly increase the voltage (and amperage as
needed) to 2.0V, 2.5V 3.0V, 4.0V, and finally to 5.0 V.
Monitor the voltage and current and click
4.. Click
5. Print a copy of the graph. Are the voltage and current proportional?
Click the Linear Fit button,
Condition #2 (51 W resistor): 6. Reconnect the power supply, 51W resistor, wires, and clips as shown in Figure 1 7. Repeat Steps 1 – 5 using the 51 W resistor. Condition #3 (6.3 V light bulb - round one): 8. Reconnect the power supply, 6.3 V light bulb - round one, wires, and clips as shown in Figure 1, replacing the 51 W resistor in the circuit with a 6.3 V light bulb (round one). 9. a. Now slowly increase the voltage (and amperage as needed) from 0.0V to 0.5 V, 1.0V, 1.5V, 2.0V, 2.5V, 3.0V, 3.5V, 4.0V, 4.5V and finally to 5.0 V. Note: do not exceed 5.0 V. otherwise the bulb may burn out. b. Note the brightness of the bulb in relationship with voltage and current. 10.
Click
11. For
Condition #3: Compare slopes of data at different parts of the curve,
first click and drag the mouse over the first 3 data points. Click the
Linear Fit button,
12. Click and
drag the mouse over the last 7 points on the graph. Click the Linear Fit
button, Condition #4 (2.5 V light bulb - thin one): 13. Reconnect the power supply, 2.5 V light bulb (thin one), wires, and clips as shown in Fig 1, replacing the 6.3 V light bulb in the circuit with a 2.5 V light bulb (thin one). 14. Now slowly increase the voltage (and amperage as needed) to 0.0V, 0.5 V, 1.0V, 1.5V, 2.0V, 2.5V and finally to 3.0 V. (ONLY GO TO 3.0V). Note: do not exceed 3.0 V, otherwise the bulb may burn out. 15. Monitor the voltage and current and click
16.
Click
17. For Condition #4: Compare slopes of data at
different parts of the curve, first click and drag the mouse over the
first 3 data points. Click the Linear Fit button,
18. Click and
drag the mouse over the last 4 points on the graph. Click the Linear Fit
button, DATA TABLE
Conclusion: (your own) ANALYSIS: 1. a. If the voltage doubles, what happens to the current? b. As the potential (Volts) across the resistor increased, the current (Amps) through the resistor increased. If the change in current is proportional to the voltage, the data should be in a straight line and it should go through zero. In these two examples how close is the y-intercept to zero? Is there a proportional relationship between voltage and current when the resistance is constant?
2. Compare the slopes in each of the above equations to the resistance of each resistor. How does the amount of resistance (Ohms) effect the slope? What does this mean?
3. Do your resistors follow Ohm’s law? (Base your answer on your experimental data.) 4. a. By observing the light bulb directly, how do you know the relative amount of current (Amps) that is going through the bulb?
b. The slope of the linear regression line is a measure of resistance. Was the change (slope) linear? Describe what happened to the amount of current (Amps) that passes through the light bulb as the potential (voltage) increased. c. Describe what happened to the amount of resistance of a light bulb as the voltage increased. d. Why do you think causes this change in resistance to the amount of current passing through a light bulb?
5. a. Does your resistors follow Ohm’s law? Explain. b. Does your light bulb follow Ohm’s law? Explain.
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