Thursday 3 Dec:

 

 

Journal: What path requires the most work done by the gas?

 

 

 

Carnot (Car-no)  Cycle:


  •  
 
  1. A high temperature Isothermal Expansion from A to B. - Heat is Supplied to the engine.
     
  2. An Adiabatic expansion cooling down from B to C.
     
  3. A low temperature Isothermal compression from C to D - Heat Removal step.
     
  4. Adiabatic compression from D to A - work performed on fluid.

 

 

 

 

 

 

 

 

 

 

 

 

A                                  B                                  C                                  D

  

 

 

1. Which graph best represents the relationship between the volume and temperature of a gas at constant pressure?

Volume (vert) vs Temp (K)  (horz)

2. Which graph best represents the relationship between the pressure and temperature of a low-density gas at constant volume? Pressure (vert) vs Temp (K)  (horz)

3. Which graph best represents plot of the average kinetic energy of the molecules of an ideal gas against the absolute temperature of that gas? KE  vs Temp (K) 

4. Which graph in the figures above best represents Boyle’s Law? Press  vs Volume

 

5. The pressure in a chamber filled with gas rises when...

 

 

 

 

 

1. A

2. A

3. A

4. B

5. Collisions between the molecules of the gas and the walls of the chamber increase due to increase of temp, decrease in volume and/or more gas particles

 

 

 

 

 

 
 
 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(6 & 7)

A piece of metal with a mass of 0.50 kilograms, specific heat of 150 cal/kg · C°, and initial temperature of 100° C is dropped into water with a mass of 2.00 kilograms, specific heat of 1,000 Cal/kg · C°, and initial temperature of 0° C.

The piece of metal is removed after 6 seconds, at which time its temperature is 40° C. Neglect any effects of heat transfer to the air or to the insulated jar.

 

6. The temperature of water after the metal is removed is? 

7. The average rate at which heat is transferred while the piece of metal is in the water is?

 

 

 

 

 

 

 

 

 

 

 

 

 

 6. Qm = mm (DTm ) cm

     Qm = (.5)(60)(150)  = 4500cal

        Qm =  QW

     QW = mw (DTw ) cw

 

          4500cal = (2)(DTw)(1000)

 

              DTw =   2.25oC

 

 

7.   4500cal/6s  =  750 cal/s

 

 

 goes down by ½, so does Temperature.

 

         

           

 

 

 

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