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1. Explain the
number and location of antinodes & nodes of the fundamental freq
(stand wave) in two resonating pipes (2.0 m), and the
l’s
of each to that of a string:
- a. One is
open at both ends
- b. one is
open at one end and closed at the other
- c. string
a. Open ended: It has
two antinodes
(always at open ends) and
one node
(in the middle). This means that the standing wave is taking up ½ of the
pipe (l
= 2L).
l
= twice the length of
the pipe or
4.0 m
frequency:
f1 = V/2L
b. One end closed: It has
one antinod
(open end) and
one node
(closed end). This means that the standing wave is taking
up 1/4 of the pipe (l
= 4L).
l
= four times the
length of the pipe or
8.0 m
frequency:
f1 = V/4L
c. String has
two nodes
(always at ends) and one antinode
(in the middle). This means that the standing wave is taking
up ½ of the string. (l
= 2L).
l
= twice the length of
the string or
4.0 m
frequency:
f1 = V/2L
(String's
l
is same as the open ended, but has 2 nodes)



2. Compare
the
intensity, frequency, amplitude, wavelength, velocity and pitch
of a point source at a distance 3d and d from the
source?
-
Intensity decreases (live all radiation &
fields of force) 1/r2 or 1/32 = 1/9th
as much
-
Frequency of sound doesn’t change due to distance
-
Amplitude is intensity: so is 1/9th as much
-
l
doesn’t change
-
Velocity doesn’t change because of distance
-
Pitch is frequency: so doesn’t change
3. Compare the frequency,
velocity, l
standing wave on a string to the sound wave generated by the string.
-
Same Frequency, the string pushes the air (compression waves) at the
same frequency of its vibration.
-
Velocity on a string is different (almost always) than the velocity
in air (which is normally about 343 m/s). V on a string depends on mass
per meter, tension, length, etc.
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